Nonstop flight route between Maamigili, Maldives and Cedar City, Utah, United States:
Departure Airport:
Arrival Airport:
Distance from VAM to CDC:
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- About this route
- VAM Airport Information
- CDC Airport Information
- Facts about VAM
- Facts about CDC
- Map of Nearest Airports to VAM
- List of Nearest Airports to VAM
- Map of Furthest Airports from VAM
- List of Furthest Airports from VAM
- Map of Nearest Airports to CDC
- List of Nearest Airports to CDC
- Map of Furthest Airports from CDC
- List of Furthest Airports from CDC
About this route:
A direct, nonstop flight between Villa International Airport (VAM), Maamigili, Maldives and Cedar City Regional Airport (CDC), Cedar City, Utah, United States would travel a Great Circle distance of 9,567 miles (or 15,396 kilometers).
A Great Circle is the shortest distance between 2 points on a sphere. Because most world maps are flat (but the Earth is round), the route of the shortest distance between 2 points on the Earth will often appear curved when viewed on a flat map, especially for long distances. If you were to simply draw a straight line on a flat map and measure a very long distance, it would likely be much further than if you were to lay a string between those two points on a globe. Because of the large distance between Villa International Airport and Cedar City Regional Airport, the route shown on this map most likely appears curved because of this reason.
Try it at home! Get a globe and tightly lay a string between Villa International Airport and Cedar City Regional Airport. You'll see that it will travel the same route of the red line on this map!
Departure Airport Information:
IATA / ICAO Codes: | VAM / VRMV |
Airport Name: | Villa International Airport |
Location: | Maamigili, Maldives |
GPS Coordinates: | 3°28'14"N by 72°50'8"E |
Area Served: | Maamigili, Alif Dhaal Atoll, Maldives |
Airport Type: | Public |
Elevation: | 6 feet (2 meters) |
# of Runways: | 1 |
View all routes: | Routes from VAM |
More Information: | VAM Maps & Info |
Arrival Airport Information:
IATA / ICAO Codes: | CDC / KCDC |
Airport Name: | Cedar City Regional Airport |
Location: | Cedar City, Utah, United States |
GPS Coordinates: | 37°42'2"N by 113°5'56"W |
Area Served: | Cedar City, Utah |
Operator/Owner: | Cedar City Corporation |
Airport Type: | Public |
Elevation: | 5622 feet (1,714 meters) |
# of Runways: | 2 |
View all routes: | Routes from CDC |
More Information: | CDC Maps & Info |
Facts about Villa International Airport (VAM):
- Maamigili Airport Airside, March 2013
- Villa International Airport (VAM) currently has only 1 runway.
- The airport resides at an elevation of 6 feet above mean sea level.
- Because of Villa International Airport's relatively low elevation of 6 feet, planes can take off or land at Villa International Airport at a lower air speed than at airports located at a higher elevation. This is because the air density is higher closer to sea level than it would otherwise be at higher elevations.
- The furthest airport from Villa International Airport (VAM) is Seymour Airport (GPS), which is located 11,252 miles (18,108 kilometers) away in Baltra Island, Galápagos Islands, Ecuador.
- The closest airport to Villa International Airport (VAM) is Ibrahim Nasir International Airport (MLE), which is located 69 miles (111 kilometers) NE of VAM.
Facts about Cedar City Regional Airport (CDC):
- SkyWest served Cedar City with 19-seat Fairchild Swearingen Metroliners, then 30-seat Embraer EMB-120 Brasilias.
- The furthest airport from Cedar City Regional Airport (CDC) is Sir Gaëtan Duval Airport (RRG), which is located 11,179 miles (17,991 kilometers) away in Rodrigues Island, Mauritius.
- The closest airport to Cedar City Regional Airport (CDC) is Panguitch Municipal Airport (PNU), which is located 40 miles (64 kilometers) ENE of CDC.
- Cedar City Regional Airport (CDC) has 2 runways.
- SkyWest Airlines provided Essential Air Service from 1972 until 2005 when Air Midwest, a subsidiary of Mesa Airlines was awarded the contract.
- Because of Cedar City Regional Airport's high elevation of 5,622 feet, planes must typically fly at a faster airspeed in order to takeoff or land at CDC. Combined with a high temperature, this could make CDC a "Hot & High" airport, where the air density is lower than it would otherwise be at sea level.